nmap和print(nm.csv())帮助需要打印出到csv.file

问题描述

我需要您帮助处理nmap脚本并将输出打印到csv文件中.当我运行脚本并使用 print(nm.csv())完成脚本时，显示了以下结果，这是我想要的第一名:

I need you help with nmap script and printing the output to csv file.When I run the script and finish it with print(nm.csv()) I got the following results displayed which is what I want first place:

host;hostname;hostname_type;protocol;port;name;state;product;extrainfo;reason;version;conf;cpe
82.214.228.176;176.228.214.82.in-addr.arpa;PTR;tcp;21;ftp;open;;;syn-ack;;3;
82.214.228.176;176.228.214.82.in-addr.arpa;PTR;tcp;22;ssh;open;;;syn-ack;;3;
82.214.228.176;176.228.214.82.in-addr.arpa;PTR;tcp;53;domain;open;;;syn-ack;;3;
82.214.228.176;176.228.214.82.in-addr.arpa;PTR;tcp;80;http;open;;;syn-ack;;3;

但是我的问题是如何重定向此文件，或者如何在我运行脚本的路径或路径中的同一目录上创建csv文件.预先感谢！

But my question is how to get this redirected or to create a csv file on the same Directory from where I run the script or maybe in a path.Thanks in advance!

推荐答案

您可以声明一个类似这样的函数

You could declare a function like this one

def save_csv_data(nm_csv, path='.'):
    with open(path + '/output.csv', 'w') as output:
        output.write(nm_csv)

然后通过传递参数，您可以指定另一个路径来保存文件，否则，请使用与脚本相同的目录:

then by passing an argument you could specify another path to save the file, or otherwise, use the same directory as the script:

if (len(sys.argv) > 1 and sys.argv[1]):
    save_csv_data(nm.csv(), path=sys.argv[1])
else:
    save_csv_data(nm.csv())

编辑:还记得 import sys

如果您决定使用参数，我也建议您使用argparse .

I also would suggest you, if you decide to use arguments, use a module like argparse.

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