本文介绍了如何从另一个类或函数中使用HashMap?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是一个工作代码示例。感谢@markspace为我提供。
这里的代码是一个hashmap并插入值。
Here is a working code example. Thanks to @markspace for providing me with it.The code here makes a hashmap and inserts values in it.
public class RpgPersonExample
{
public static void main( String[] args )
{
Map<String, RpgPerson> team = new HashMap<>();
team.put( "Sgt. Mayhem", new RpgPerson( 100, 10, 0 ) );
team.put( "Wizard", new RpgPerson( 100, 1, 10 ) );
team.put( "Dragon", new RpgPerson( 1000, 100, 100 ) );
System.out.println( team.get( "Dragon" ) );
System.out.println( team.get( "Wizard" ) );
}
}
class RpgPerson
{
private int hits;
private int strength;
private int magic;
public RpgPerson( int hits, int strength, int magic )
{
this.hits = hits;
this.strength = strength;
this.magic = magic;
}
@Override
public String toString()
{
return "RpgPerson{" + "hits=" + hits + ", strength=" +
strength + ", magic=" + magic + '}';
}
}
从另一个类中使用它。如果我使用
What I want to do though is to use it from another class. If I use
System.out.println( team.get( "Dragon" ) );
从主函数它工作正常。但是我该怎么做,我想从另一个类做呢?
from the main function it works fine. But how should I do i I want to do it from another class?
Public class Test {
public static void example(){
System.out.println( RpgPerson.team.get( "Dragon" ) );
}
}
Test类明显不起作用,
The class Test does obviously not work but what should I do if I want it to work?
推荐答案
你可以做的最简单的事情是传入示例方法一个参数,引用 Map
:
The simplest thing you can do is pass into the example method an argument that references the Map
:
public static void example(Map<String, RpgPerson> team) {
System.out.println(team.get("Dragon"));
}
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