Swift版本的componentsSeparatedByString

问题描述

我知道它的noob问题，我真的在搜索之前搜索。但对于我想知道的内容并没有确切的答案。
如何在不使用Objective C的情况下将字符串拆分为数组？例如：

I know its noob question, i really search around before ask. But there is not exact answer of what i want to know. How we split string into the array without using Objective C? For example:

var str = "Today is so hot"
var arr = str.componentsSeparatedByString(" ")  // *

• 我知道它不起作用但我正在寻找像那。我想用（或其他字符/字符串）拆分字符串



想法：这对我来说可能非常好，进行扩展字符串类。但我不知道我是怎么做到的。

Idea:It might be very good for me, making extension of string class. But i dont know how i do that.

编辑：忘记导入基础。如果我导入基础它将工作。但有没有办法扩展String类？
谢谢

Forgetting import Foundation. If I import foundation it will work. But is there any way to do with extending String class?Thank you

推荐答案

如果你想按给定的字符分割字符串那么你可以使用
内置的 split（）方法，而不需要基金会：

If you want to split a string by a given character then you can use thebuilt-in split() method, without needing Foundation:

let str = "Today is so hot"
let arr = split(str, { $0 == " "}, maxSplit: Int.max, allowEmptySlices: false)
println(arr) // [Today, is, so, hot]

Swift 1.2的更新：使用Swift 1.2（Xcode 6.3）更改参数的顺序，比较：

Update for Swift 1.2: The order of the parameters changed with Swift 1.2 (Xcode 6.3), compare split now complains about missing "isSeparator":

let str = "Today is so hot"
let arr = split(str, maxSplit: Int.max, allowEmptySlices: false, isSeparator: { $0 == " "} )
println(arr) // [Today, is, so, hot]

Swift 2的更新：参见。

Swift 3的更新：

let str = "Today is so hot"
let arr = str.characters.split(separator: " ").map(String.init)
print(arr)

这篇关于Swift版本的componentsSeparatedByString的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！