本文介绍了Java参考分配与通用列表的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我觉得很蠢，要求我这样。
I feel stupid asking this but I am.
< MyCompany>
Now the list has broken the generic guarantee because you have list that was declared as <MyCompany> with a MyPerson in it.
b
$ b
You could cast it like this.
public void myMethod(List<MyCompany> list){
List<? extends HasId> ids = list;
}
但不允许add（）操作，如果你愿意，得到id。
But add() operations will not be permitted, but you can iterate it to get the id if you wish.
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