问题描述
我正在尝试在PySpark应用程序中广播用户定义的变量,但始终出现以下错误:
I am trying to broadcast a user defined variable in a PySpark application but I always have the following error:
File "/usr/local/spark-2.1.0-bin-hadoop2.7/python/lib/pyspark.zip/pyspark/worker.py", line 174, in main
process()
File "/usr/local/spark-2.1.0-bin-hadoop2.7/python/lib/pyspark.zip/pyspark/worker.py", line 169, in process
serializer.dump_stream(func(split_index, iterator), outfile)
File "/usr/local/spark-2.1.0-bin-hadoop2.7/python/lib/pyspark.zip/pyspark/serializers.py", line 268, in dump_stream
vs = list(itertools.islice(iterator, batch))
File "/home/.../sparkbroad.py", line 29, in <lambda>
output = input_.map(lambda item: b.value.map(item))
File "/usr/local/spark-2.1.0-bin-hadoop2.7/python/lib/pyspark.zip/pyspark/broadcast.py", line 106, in value
self._value = self.load(self._path)
File "/usr/local/spark-2.1.0-bin-hadoop2.7/python/lib/pyspark.zip/pyspark/broadcast.py", line 97, in load
return pickle.load(f)
AttributeError: 'module' object has no attribute 'FooMap'
模块sparkbrad.py
中的代码如下:
import random
import pyspark as spark
class FooMap(object):
def __init__(self):
keys = list(range(10))
values = [2 * key for key in keys]
self._map = dict(zip(keys, values))
def map(self, value):
if value not in self._map:
return -1
return self._map[value]
class FooMapJob(object):
def __init__(self, inputs):
self._inputs = inputs
self._foomap = FooMap()
def run(self):
sc = spark.SparkContext('local', 'FooMap')
input_ = sc.parallelize(self._inputs, 4)
b = sc.broadcast(self._foomap)
output = input_.map(lambda item: b.value.map(item))
b.unpersist()
result = list(output.toLocalIterator())
sc.stop()
return result
def main():
inputs = [random.randint(0, 10) for _ in range(10)]
job = FooMapJob(inputs)
print(job.run())
if __name__ == '__main__':
main()
我正在通过以下方式运行它:
and I am running it via the:
:~$ spark-submit --master local[4] --py-files sparkbroad.py sparkbroad.py
我在其中添加了--py-files
参数的地方,但看起来并没有太大变化.不幸的是,我找不到在线处理复杂类(只是列表或词典)广播的任何示例.任何提示表示赞赏.预先感谢.
where I have added the --py-files
argument but it looks it doesn't change that much. Unfortunately, I could not find any example online dealing with broadcasting of complex classes (just lists or dictionaries). Any hint is appreciated. Thanks in advance.
更新:将FooMap
类放在单独的模块中,即使没有--py-files
指令,一切也可以正常工作.
UPDATE: placing the FooMap
class in a separate module, everything seems working fine, even without the --py-files
directive.
推荐答案
将FooMap
类放在单独的模块中,一切正常.
Placing the FooMap
class in a separate module, everything works fine.
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