SQL Server 2012 中的 group_concat 与 ORDER BY 另一列

问题描述

我有一个包含大约一百万个这样的条目的表:

I have a table containing ~ a million entries like this:

customer_id | purchased_at     | product
1           | 2012-06-01 00:00 | apples
1           | 2012-09-02 00:00 | apples
1           | 2012-10-01 00:00 | pears
2           | 2012-06-01 00:00 | apples
2           | 2012-07-01 00:00 | apples
3           | 2012-09-02 00:00 | pears
3           | 2012-10-01 00:00 | apples
3           | 2012-10-01 01:00 | bananas

我想将产品连接到一行，DISTINCT 并按购买的_at 的顺序

I want to concatenate the products to one row, DISTINCT and in order of the purchased_at

在 MySQL 中我只使用

In MySQL I just use

select customer_id, min(purchased_at) as first_purchased_at,
group_concat(DISTINCT product order by purchased_at) as all_purchased_products
from purchases group by customer_id;

得到

customer_id | first_purchased_at | all_purchased_products
1           | 2012-06-01 00:00 | apples, pears
2           | 2012-06-01 00:00 | apples
3           | 2012-09-02 00:00 | pears, apples, bananas

如何在 SQL Server 2012 中做到这一点?

How can I do that in SQL Server 2012?

我尝试了以下hack"，它有效，但它是一种矫枉过正，并且在长桌子上表现不佳

I tried the following 'hack', which works, but it's an overkill and doesn't perform well on a long table

select
customer_id,
min(purchased_at) as first_purchased_at,
stuff ( ( select  ',' +  p3.product
          from (select  p2.product, p2.purchased_at,
          row_number() over(partition by p2.product order by p2.purchased_at) as seq
          from  purchases p2 where
          p2.customer_id = p1.customer_id ) p3
          where p3.seq = 1 order by p3.purchased_at
          for XML PATH('') ), 1,1,'') AS all_purchased_products
from purchases p1
group by customer_id;

我该怎么做才能解决这个问题?

What can I do to solve this?

推荐答案

我不确定这是否会更快，但这里有一个替代版本，您无需加入两次购买在 STUFF() 中:

I am not sure if this will be any faster, but here is an alternate version where you don't join on purchases twice in the STUFF():

select customer_id,
  min(purchased_at) as first_purchased_at,
  stuff ((select ',' +  p2.product
          from
          (
            select product, customer_id,
                ROW_NUMBER() over(partition by customer_id, product order by purchased_at) rn,
                ROW_NUMBER() over(partition by customer_id order by purchased_at) rnk
            from purchases
          ) p2
          where p2.customer_id = p1.customer_id
            and p2.rn = 1
          group by p2.product, rn, rnk
          order by rnk
          for XML PATH('') ), 1,1,'') AS all_purchased_products
from purchases p1
group by customer_id;

参见SQL Fiddle with Demo

结果:

| CUSTOMER_ID |               FIRST_PURCHASED_AT | ALL_PURCHASED_PRODUCTS |
---------------------------------------------------------------------------
|           1 |      June, 01 2012 00:00:00+0000 |           apples,pears |
|           2 |      June, 01 2012 00:00:00+0000 |                 apples |
|           3 | September, 02 2012 00:00:00+0000 |   pears,apples,bananas |

这篇关于SQL Server 2012 中的 group_concat 与 ORDER BY 另一列的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！