问题描述
可以通过编程方式添加/删除 ABPersonCopyArrayOfAllLinkedPeople 返回的CFArray中的联系人，从而有效地链接和取消链接来自各种来源的不同联系人记录，以在iOs中显示为统一电话簿？
Can one programmatically add/remove the contacts inside the CFArray returned by ABPersonCopyArrayOfAllLinkedPeople, thus, effectively, linking and un-linking different records of contacts from various sources to show as "unified" in the iOs phone book?
推荐答案
据我所知，没有公开API用于链接或取消链接联系人，至少在iOS 6 SDK中。但是，您似乎可以通过调用未记录的私有函数 bool ABPersonLinkPerson（ABRecordRef from，ABRecordRef to）来创建联系人之间的链接。该签名可能不完全正确 - 我没有对此进行过彻底的测试。
As far as I've been able to determine, there is no public API exposed for linking or unlinking contacts, at least in the iOS 6 SDK. However, it does appear that you can create links between contacts by calling the undocumented, private function bool ABPersonLinkPerson(ABRecordRef from, ABRecordRef to). That signature may not be exactly right--I haven't tested this too thoroughly.
如果您使用私有API，您的应用程序当然不太可能获得批准，但是，如果你试图为了单元测试而制作一个假的地址簿，并且你想要一些相关的联系人，那么这可能很有用。
Your app is of course unlikely to be approved if you make use of private APIs, but if you're trying to, say, make a fake address book for the sake of unit testing and you want some linked contacts in that, this could be useful.
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