本文介绍了Django InlineModelAdmin给出错误“ MediaDefiningClass”对象不可迭代的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

来自models.py

From models.py

class Indicator(models.Model):
    name = models.CharField(max_length=50)
    youtube = models.CharField(max_length=LONG_BLOG_POST_CHAR_LEN)
    description = models.CharField(max_length=LONG_BLOG_POST_CHAR_LEN)    
    recommendation = models.CharField(max_length=LONG_BLOG_POST_CHAR_LEN)
    isPublic = models.BooleanField(default=False)
    methods_path = models.CharField(max_length=100,default=None)
    meta_description = models.CharField(max_length=150,default='')
    image_path = models.CharField(max_length=100,blank=True)

    def __str__(self):
        return self.name   

class IndicatorParameterInt(models.Model):
    name = models.CharField(max_length=50)
    value = models.IntegerField(default=1)
    indicator_int_parameter = models.ForeignKey(Indicator, on_delete=models.CASCADE)
    hidden = models.BooleanField(default=False)

class IndicatorParameterFloat(models.Model):
    name = models.CharField(max_length=50)
    setting = models.FloatField(default=1)
    indicator_float_parameter = models.ForeignKey(Indicator, on_delete=models.CASCADE)
    hidden = models.BooleanField(default=False)

class Comparison(models.Model):
    name = models.CharField(max_length=100)

来自admin.py

From admin.py

from django.contrib import admin
from .models import *

# Register your models here.
admin.site.register( MarketData )
admin.site.register( Indicator )
admin.site.register( UserProfile )



class IndicatorParameterIntInline(admin.TabularInline):
    model = IndicatorParameterInt
    fk_name = "indicator_int_parameter"

class IndicatorParameterFloatInline(admin.TabularInline):
    model = IndicatorParameterFloat
    fk_name = "indicator_float_parameter"   

class ComparisonInline(admin.TabularInline):
    model = Comparison
    fk_name = "Comparison"  

class IndicatorInline(admin.ModelAdmin):
    inlines = [ 
                IndicatorParameterIntInline,
                IndicatorParameterFloatInline,
                ComparisonInline, 
              ]

admin.site.unregister( Indicator )
admin.site.register( IndicatorInline )

错误 TypeError: MediaDefiningClass对象不可迭代在admin的最后一行出现:admin.site.register(IndicatorInline)。我尝试先注册IndicatorInline还是任何外键类都没有关系。

The error TypeError: 'MediaDefiningClass' object is not iterable comes up on the final line of admin: admin.site.register( IndicatorInline ). It doesn't matter if I try to register IndicatorInline first or any of the foreign key classes.

我引用了,鼓励使用fk_name属性。不管我是否使用fk_name,都会发生错误。

I referenced this post, which encouraged using the fk_name attribute. The error occurs regardless of whether or not I use fk_name.

推荐答案

首先,请尽量不要使用 import * -始终导入您正在使用的模型。

First of all, try not to use import * - always import the model that you are using.

接下来,我认为更改此设置就足够了

Next, I think changing this should be enough

from django.contrib import admin
from .models import *





class IndicatorParameterIntInline(admin.TabularInline):
    model = IndicatorParameterInt
    fk_name = "indicator_int_parameter"

class IndicatorParameterFloatInline(admin.TabularInline):
    model = IndicatorParameterFloat
    fk_name = "indicator_float_parameter"   

class ComparisonInline(admin.TabularInline):
    model = Comparison
    fk_name = "Comparison"  

class IndicatorInline(admin.ModelAdmin):
    inlines = [ 
                IndicatorParameterIntInline,
                IndicatorParameterFloatInline,
                ComparisonInline, 
              ]

admin.site.register(Indicator, IndicatorInline)
admin.site.register(MarketData, )
admin.site.register(UserProfile, )

这篇关于Django InlineModelAdmin给出错误“ MediaDefiningClass”对象不可迭代的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

11-02 12:52