等待与不同的结果多任务

问题描述

我有3个任务：

private async Task<Cat> FeedCat() {}
private async Task<House> SellHouse() {}
private async Task<Tesla> BuyCar() {}

他们都需要运行之前，我的code可以继续，我需要从每个结果也是如此。结果都没有什么共同点相互

They all need to run before my code can continue and I need the results from each as well. None of the results have anything in common with each other

我如何打电话等待了3个任务完成，然后得到的结果？

How do I call and await for the 3 tasks to complete and then get the results?

推荐答案

在使用后 WhenAll ，您可以用出单独拉动的结果等待：

var catTask = FeedCat();
var houseTask = SellHouse();
var carTask = BuyCar();

await Task.WhenAll(catTask, houseTask, carTask);

var cat = await catTask;
var house = await houseTask;
var car = await carTask;

您也可以使用 Task.Result （因为你知道凭这一点，他们都成功完成）。不过，我建议使用伺机，因为它显然是正确的，而结果可能会导致其他情况下的问题。

You can also use Task.Result (since you know by this point they have all completed successfully). However, I recommend using await because it's clearly correct, while Result can cause problems in other scenarios.

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