Jenkins脚本化管道中的分支指定符正则表达式

问题描述

假设我想为同一脚本管道下的不同分支定义管道，如何为某些分支模式定义正则表达式.例如说:-

Suppose i want to define pipeline for different branches under same scripted pipeline, how to define the regex for certain pattern of branches. Say for example :-

if(env.BRANCH_NAME ==~ /release.*/){
	 stage("Deploy"){
		echo 'Deployed release to QA'
	 }

在这里，我想以这种方式为模式的任何分支定义该正则表达式

Here i want to define that regex in such a way for any branch of the pattern

*release*

(表示其中包含释放字符串的任何分支).如何实现?

(meaning any branch with release string in it).How to achieve that?

类似地，如何实现类似:-

And similarly how to achieve something like :-

如果分支除了开发之外，请掌握，发布(模式).

if the branch is anything but develop, master, release(pattern).

推荐答案

如果您使用的是Groovy，则可以使用以下内容

If you're using groovy you may use the following

if ((env.BRANCH_NAME =~ '.*release.*').matches()) {
    stage("Deploy"){
        echo 'Deployed release to QA'
    }
}

如果要匹配除develop，master或release以外的任何分支名称，则可以使用以下正则表达式

And if you want to match any branch name but develop, master or release, you may use the following regex

if ((env.BRANCH_NAME =~ '^((?!develop|master|release).)*$').matches()) {
    stage("Deploy"){
        echo 'Deployed release to QA'
    }
}

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