WorkManager OneTimeWorkRequest InitialDelay在设定的时间之后工作

本文介绍了WorkManager OneTimeWorkRequest InitialDelay在设定的时间之后工作的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

WorkManager.getInstance(activity).enqueueUniquePeriodicWork("test_work",
                                                ExistingPeriodicWorkPolicy.KEEP,
                                                PeriodicWorkRequest.Builder(MyWorker::class.java,
                                                        15, TimeUnit.MINUTES)
                                                        .build())

现在我正在使用PeriodicWork，并且即使我第一次尝试取消了uniquettask，现在doWork()也被调用了两次.我得到了两次Notification(通知)，并且也已登录Log(记录两次).

Now I'm using PeriodicWork and now doWork() called twice even I cancelled uniquettask at first attempt.I'm getting Notification twice and Checked in Log also It's called twice.

override fun doWork(): Result {


            if (checkTaskFinished()) {
                Logger.e("checkXXX----Hurrayyyy  ☻♥☺")
                val notificationUtils: NotificationUtils = NotificationUtils(applicationContext)
                notificationUtils.showNotificationMessage("Readddd", "rwaeaeae.", 2)


                WorkManager.getInstance(context).cancelUniqueWork("test_work")
            }

    return Result.success()

}

OLD

我遇到了 WorkManager OneTimeWorkRequest setInitialDelay 的问题.

OLD

I'm facing problem with WorkManager OneTimeWorkRequest setInitialDelay.

当应用程序位于前景或最近列表中时，它可以很好地工作.但是，当我从最近的列表中删除App时，一切都搞砸了.

It's work fine when app is in forground or in recent list. But When I remove App from recent list everything is messed up.

我想实现什么?-我想在几个任务挂起后几个小时后向用户发送通知，因此在进行一些R& D开始使用 WorkManager 进行工作之后，因为它可以调度任务而没有后台服务限制.

What I want to achieve ?- I want send notification to user after few hours when some task is pending ,so after some R&D start work using WorkManager because of It's ability to Schedule Tasks without background service limitation.

    Constraints constraints = new Constraints.Builder()
                                .setRequiresBatteryNotLow(true)
                                .build();

    final OneTimeWorkRequest simpleRequest = new OneTimeWorkRequest.Builder(MyWorker.class)
            .setInitialDelay(3, TimeUnit.MINUTES)
            .setConstraints(constraints)
            .addTag("simple_work")
            .build();

    WorkManager workManager = WorkManager.getInstance();

    workManager.beginUniqueWork("simple_work", ExistingWorkPolicy.KEEP, simpleRequest).enqueue();

工人阶级

    public class MyWorker extends Worker {
    private NotificationUtils notificationUtils;
    public static final String EXTRA_OUTPUT_MESSAGE = "output_message";

    public MyWorker(@NonNull Context context, @NonNull WorkerParameters workerParams) {
        super(context, workerParams);
    }

    @NonNull
    @Override
    public Result doWork() {

        notificationUtils = new NotificationUtils(getApplicationContext());
        notificationUtils.showNotificationMessage("TITLE", "This is a MESSEAGE",2);

        Data output = new Data.Builder()
                .putString(EXTRA_OUTPUT_MESSAGE, "I have come from MyWorker!")
                .build();

        setOutputData(output);

        return Result.SUCCESS;
    }


}

所以，请指导我做错了什么，或者不是我在一次设置的特定时间的计划任务.完成后，我不想保留重复的工作.我要在完成第一个OneTimeWorkRequest之后创建新的，所以它必须按照记录的 beginUniqueWork 正常工作.

So ,Please guide me what I do wrong or It's not for schedule task at specific time which I set for once. I don't want to keep repeat work after It's done. I'm create just new after finish first OneTimeWorkRequest so It has to work fine as per documented beginUniqueWork.

英语不是我的母语，所以请原谅我在语法上的错误:)

English isn't my native language so pardon me for grammatically mistake:)

When

WorkManager OneTimeWorkRequest InitialDelay在设定的时间之后工作

问题描述

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