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问题描述
我很好奇Python是否为sklearn.tree.decisiontreeclassifier提供了as_formula说明符(例如statsmodels中的说明符)，或者采用某种方式侵入其中.目前，我必须使用
I was curious if there is an as_formula specifier (like in statsmodels) for sklearn.tree.decisiontreeclassifier in Python, or some way to hack one in. Currently, I must use
clf = tree.DecisionTreeClassifier()
clf = clf.fit(X, Y)
但是我更喜欢
clf = clf.fit(formula='Y ~ X', data=df)
原因是我想指定一个以上的X，而不必进行大量的数组整形.谢谢.
The reason is that I would like to specify more than one X without having to do a lot of array shaping. Thanks.
推荐答案
目前尚不可能，但是为scikit-learn提供一个patsy接口将是很棒的.不过，我认为目前没有人对此进行研究.
It's currently not possible, but it would be great to have a patsy interface for scikit-learn. I don't think anyone is working on it at the moment, though.
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