反向正则表达式，从正则表达式创建字符串

将字符串/URL 转换为一组匹配的标准以在 MVC 中使用是很容易的，但反过来说……不幸的是，情况并非如此. 解决方案 是的，这是可能的！对于这种情况，我编写了以下解决方案:$regex = '#^en/cities/([^/]+?)/$#';$replace = array('巴黎');$result = preg_replace_callback('#^\^|\([^)]*\)|\$$#', function($m)use($replace){静态 $index = 0;if($m[0] === '^' || $m[0] === '$'){return '';}if(isset($replace[$index])){返回 $replace[$index++];}返回 $m[0];}, substr($regex, 1, -1));回声 $result;//en/城市/巴黎/在线演示我让它变得灵活"，所以你可以添加更多的价值！$regex = '#^en/cities/([^/]+?)/region/([^/]+?)$#';//<<<改变了$replace = array('巴黎', 'nord');//<<<改变了$result = preg_replace_callback('#^\^|\([^)]*\)|\$$#', function($m)use($replace){静态 $index = 0;if($m[0] === '^' || $m[0] === '$'){return '';}if(isset($replace[$index])){返回 $replace[$index++];}返回 $m[0];}, substr($regex, 1, -1));回声 $result;//en/cities/paris/region/nord在线演示说明:$regex = '#^en/cities/([^/]+?)/region/([^/]+?)$#';//正则表达式反转"$replace = array('巴黎', 'nord');//要注入"的值/* 正则表达式解释:# 开始分隔符^\^ 在开头匹配^"(我们想摆脱这个)|或者\([^)]*\) 匹配("，任何零次或多次，直到找到)"，)"|或者\$$ 匹配末尾的$"(我们想解决这个问题)# 结束分隔符*/$result = preg_replace_callback('#^\^|\([^)]*\)|\$$#', function($m)use($replace){静态 $index = 0;//设置索引0，注意这个变量只能在这个(匿名)函数中访问if($m[0] === '^' || $m[0] === '$'){return '';}//在开始和结束时使用 ^/$if(isset($replace[$index])){//总是检查它是否存在，例如如果 $replace 中没有足够的值，这将防止错误...返回 $replace[$index++];//返回注入的值，同时将 $index 增加 1}返回 $m[0];//如果没有足够的值，这将返回 ([^/]+?) 在这种情况下，您可能希望将其删除以不将其包含在输出中}, substr($regex, 1, -1));//substr($regex, 1, -1) =>使用分隔符回声 $result;//输出 o_o注意:这仅适用于 PHP 5.3+I am working on a multilingual site and have chosen to use custom URLs per language as well, so for example:/en/cities/paris//nl/steden/paris/Both point to the Index method of the Cities controller.On every page there's an option to switch language and it will look in my routes to match controller, view and language.So if I'm on the Dutch page, it will find the proper url for the English version, which will be 'cities' instead of 'steden'.All worked fine, up until I started using more complex regular expressions.I have these regular expressions that will match my desired URLs:#^en/cities/([^/]+?)/$##^nl/steden/([^/]+?)/$#In my code I have access to the variable that's being matched, 'paris' in this example. Would it be possible to 'reverse' this regular expression and have it print 'en/cities/paris/'If not.. how would I go about having links to different versions of the same page, considering the URLs are different.. preferably have it as programmable as possible.In a somewhat similar question, someone answered (http://stackoverflow.com/a/7070734/616398) that the essense of regex is to match an infinite number of results.. so it might not be possible.It's quite easy to go from a string/URL to a set of matched criteria to use in a MVC, but the other way around.. not so much, unfortunately. 解决方案 Yes that's possible ! For this case I've coded the following solution:$regex = '#^en/cities/([^/]+?)/$#';$replace = array('paris');$result = preg_replace_callback('#^\^|\([^)]*\)|\$$#', function($m)use($replace){ static $index = 0; if($m[0] === '^' || $m[0] === '$'){return '';} if(isset($replace[$index])){ return $replace[$index++]; } return $m[0];}, substr($regex, 1, -1));echo $result; // en/cities/paris/Online demoI've made it "flexible" so you can add more values to it !$regex = '#^en/cities/([^/]+?)/region/([^/]+?)$#'; // <<< changed$replace = array('paris', 'nord'); // <<< changed$result = preg_replace_callback('#^\^|\([^)]*\)|\$$#', function($m)use($replace){ static $index = 0; if($m[0] === '^' || $m[0] === '$'){return '';} if(isset($replace[$index])){ return $replace[$index++]; } return $m[0];}, substr($regex, 1, -1));echo $result; // en/cities/paris/region/nordOnline demoExplanation:$regex = '#^en/cities/([^/]+?)/region/([^/]+?)$#'; // Regex to "reverse"$replace = array('paris', 'nord'); // Values to "inject"/* Regex explanation: # Start delimiter ^\^ Match "^" at the begin (we want to get ride of this) | Or \([^)]*\) Match "(", anything zero or more times until ")" is found, ")" | Or \$$ Match "$" at the end (we want to get ride of this) # End delimiter*/$result = preg_replace_callback('#^\^|\([^)]*\)|\$$#', function($m)use($replace){ static $index = 0; // Set index 0, note that this variable is only accessible in this (anonymous) function if($m[0] === '^' || $m[0] === '$'){return '';} // Get ride of ^/$ at the begin and the end if(isset($replace[$index])){ // Always check if it exists, for example if there were not enough values in $replace, this will prevent an error ... return $replace[$index++]; // Return the injected value, at the same time increment $index by 1 } return $m[0]; // In case there isn't enough values, this will return ([^/]+?) in this case, you may want to remove it to not include it in the output}, substr($regex, 1, -1)); // substr($regex, 1, -1) => Get ride of the delimitersecho $result; // output o_o Note: This works only on PHP 5.3+ 这篇关于反向正则表达式，从正则表达式创建字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！