问题描述
我有一个整数数组列表,我需要计算除最小的两个整数外的所有整数的平均值.我一直在尝试不同的方法,但是我想做的就是找到min1,将其删除,然后找到min2,然后将其删除.
I have an arraylist of integers, i need to compute the average of the integers excluding the smallest two integers. I keep trying different ways of doing this but think what I want to do is find min1, remove it and then find min2 then remove that.
public double computeAverageWithoutLowest2()
{
ArrayList<Student> newscores = new ArrayList<Student>(scores);
int newtotalScores=0;
int newavg=0;
int min1 = 0;
int min2 = 0;
min1 = newscores.get(0).getScore();
for (int i = 0; i< newscores.size(); i++)
{
if (newscores.get(i).getScore() < min1)
{
min1 = newscores.get(i).getScore();
}
}
现在我要从阵列列表中删除min1.我显然尝试过newscores.remove(min1);这不起作用.如何找出数组min1中的哪个位置,然后将其删除?
now I want to remove min1 from my arraylist. I have obviously tried newscores.remove(min1); which does not work. How can I figure out what spot in the array min1 is and then delete it?
任何帮助都将非常感谢!
Any help would be great thanks!!
好的,现在在查看注释后,我将代码更改为:
Alright so now after looking at the comments I changed my code to:
ArrayList<Student> newscores = new ArrayList<Student>(scores);
int newtotalScores=0;
int newavg=0;
int minPos1 = 0;
int minPos2 = 0;
int min1 = newscores.get(0).getScore();
int min2 = newscores.get(0).getScore();
for(int i = 0; i < newscores.size(); i++)
{
if(newscores.get(i).getScore() < min1)
{
min1 = scores.get(i).getScore();
minPos1 = i;
}
}
newscores.remove(minPos1);
for(int j = 0; j < newscores.size(); j++)
{
if(newscores.get(j).getScore() < min2)
{
min2 = scores.get(j).getScore();
minPos2 = j;
}
}
newscores.remove(minPos2);
这种方法可以删除min1,但不能删除min2,而是只删除与min1相同的位置.
This way works to remove min1, but does not work to remove min2 instead it just removes the same position that min1 removed.
推荐答案
为什么不简单地使用 remove
, indexOf
和 min
:
Why don't you simply use remove
, indexOf
and min
:
newscores.remove(newscores.indexOf(Collections.min(newscores)));
如果要删除两个最小的项目,请重复两次.
Do it twice if you want to remove the two smallest items.
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