c++ - 功能计时器防止电源继续

我刚来这地方。我的C++大学类(class)结束后有点使用rust 。我正在尝试制作一个程序，其中特定的击键记录了cout中看到的文本。我遇到的问题是计时器函数阻止主函数继续运行。设置计时器函数是为了使每次延迟达到28时，将 Tic 增加1。计时器循环并达到28时，延迟重置为0。为什么不是我的ojit__strong继续吗？是否正在等待计时器完成循环？如何使计时器和主同时工作？这不是家庭作业。制作个人项目。

#include <Windows.h>
#include <iostream>
#include <fstream>
#include <stdio.h>
#include <string>

using namespace std;

int Tic = 0;
int Delay = 0;

bool KeyIsListed(int iKey)
{
switch (iKey)
{
    case 0x41:
        cout << "ACS_Execute(10,0,0,0,0);\n"; //the A Note
        cout << "Delay("<<Tic<<");\n"; //Capture the time
        Delay = 0;
        Tic = 0
        break;
    case 0x53:
        cout << "ACS_Execute(11,0,0,0,0);\n"; //the S Note
        cout << "Delay("<<Tic<<");\n"; //Capture the time
        Delay = 0;
        Tic = 0
        break;
    case 0x44:
        cout << "ACS_Execute(12,0,0,0,0);\n"; //the D Note
        cout << "Delay("<<Tic<<");\n"; //Capture the time
        Delay = 0;
        Tic = 0
        break;
    case 0x46:
        cout << "ACS_Execute(13,0,0,0,0);\n"; //the F Note
        cout << "Delay("<<Tic<<");\n"; //Capture the time
        Delay = 0;
        Tic = 0
        break;
    case 0x47:
        cout << "ACS_Execute(14,0,0,0,0);\n"; //the G Note
        cout << "Delay("<<Tic<<");\n"; //Capture the time
        Delay = 0;
        Tic = 0
        break;
    case 0x48:
        cout << "ACS_Execute(15,0,0,0,0);\n"; //the H Note
        cout << "Delay("<<Tic<<");\n"; //Capture the time
        Delay = 0;
        Tic = 0
        break;
    case 0x4A:
        cout << "ACS_Execute(16,0,0,0,0);\n"; //the J Note
        cout << "Delay("<<Tic<<");\n"; //Capture the time
        Delay = 0;
        Tic = 0
        break;
    case 0x4B:
        cout << "ACS_Execute(17,0,0,0,0);\n"; //the K Note
        cout << "Delay("<<Tic<<");\n"; //Capture the time
        Delay = 0;
        Tic = 0
        break;
    case 0x4C:
        cout << "ACS_Execute(18,0,0,0,0);\n"; //the L Note
        cout << "Delay("<<Tic<<");\n"; //Capture the time
        Delay = 0;
        Tic = 0
        break;
    }
}

int timer()//Doom Tic timer
{
    while(TRUE)
    {
        if(Delay == 28)//Aprox to 1 tic
        {
            Delay = 0;//Reset delay to 0
            Tic ++;//Increase Tic by 1
        }
        else
        {
            Delay ++;//Increase Delay until it is at 28
        }
        Sleep(0.1);
    }
}

int main()
{
char key;
timer();//Call timer Function (This is preventing the main function from continuing)
while(TRUE)
{
    for(key = 8; key <= 190; key ++)
    {
        if(GetAsyncKeyState(key) == 1)
        {
            if(KeyIsListed(key) == FALSE)
            {

            }
        }
    }

}
return 0;

}

最佳答案

  while(TRUE)
    {
        if(Delay == 28)//Aprox to 1 tic
        {
            Delay = 0;//Reset delay to 0
            Tic ++;//Increase Tic by 1
        }
        else
        {
            Delay ++;//Increase Delay until it is at 28
        }
        Sleep(0.1);
    }

这是不可能的。您是要在break块中放入if吗？或while (Delay > 0)(最初设置为1)。

另外，如注释中所述，如果您说一个函数返回int，则需要确保它在每个路径上都有一个return语句。也许不是break，而是只想要return Tic;？

关于c++ - 功能计时器防止电源继续，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/51529123/