javascript - 组合filter()和startsWith()以过滤数组

假设我有一个数组常量，如下所示：

const people = [
      { first: 'John', last: 'Doe', year: 1991, month: 6 },
      { first: 'Jane', last: 'Doe', year: 1990, month: 9 },
      { first: 'Jahn', last: 'Deo', year: 1986, month: 1 },
      { first: 'Jone', last: 'Deo', year: 1992, month: 11 },
      { first: 'Jhan', last: 'Doe', year: 1989, month: 4 },
      { first: 'Jeon', last: 'Doe', year: 1992, month: 2 },
      { first: 'Janh', last: 'Edo', year: 1984, month: 7 },
      { first: 'Jean', last: 'Edo', year: 1981, month: 8},
];

我想回报80年代出生的每个人的价值。

我当前实现此目的的功能是：

const eighty = people.filter(person=> {
    if (person.year >= 1980 && person.year <= 1989) {
        return true;
    }
});

我的问题：是否可以将startsWith()和filter()一起使用来替换：

if (person.year >= 1980 && person.year <= 1989) {
    return true;
}

用startsWith('198')代替？

如果是，那么正确的方法是什么？

最佳答案

你可以做

people.filter(person => String(person.year).startsWith('198'))

const people = [
      { first: 'John', last: 'Doe', year: 1991, month: 6 },
      { first: 'Jane', last: 'Doe', year: 1990, month: 9 },
      { first: 'Jahn', last: 'Deo', year: 1986, month: 1 },
      { first: 'Jone', last: 'Deo', year: 1992, month: 11 },
      { first: 'Jhan', last: 'Doe', year: 1989, month: 4 },
      { first: 'Jeon', last: 'Doe', year: 1992, month: 2 },
      { first: 'Janh', last: 'Edo', year: 1984, month: 7 },
      { first: 'Jean', last: 'Edo', year: 1981, month: 8},
];

var filtered = people.filter(p => String(p.year).startsWith('198'));

console.log(filtered);

关于javascript - 组合filter()和startsWith()以过滤数组，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/50030338/