c# - 如何将流程输出(控制台)重定向到richtextbox？

这是什么问题，为什么richtextbox无法获取Process输出流？ richtextbox中没有文本显示。

 private void button1_Click(object sender, EventArgs e)
    {

        Process sortProcess;
        sortProcess = new Process();
        sortProcess.StartInfo.FileName = "sort.exe";
        sortProcess.StartInfo.Arguments = this.comboBox1.SelectedItem.ToString();
        // Set UseShellExecute to false for redirection.
        sortProcess.StartInfo.CreateNoWindow = true;
        sortProcess.StartInfo.UseShellExecute = false;



        // Redirect the standard output of the sort command.
        // This stream is read asynchronously using an event handler.
        sortProcess.StartInfo.RedirectStandardOutput = true;
        sortOutput = new StringBuilder("");

        // Set our event handler to asynchronously read the sort output.
        sortProcess.OutputDataReceived += new DataReceivedEventHandler(SortOutputHandler);

        // Redirect standard input as well.  This stream
        // is used synchronously.
        sortProcess.StartInfo.RedirectStandardInput = true;

        // Start the process.
        sortProcess.Start();



        // Start the asynchronous read of the sort output stream.
        sortProcess.BeginOutputReadLine();
        sortProcess.WaitForExit();


        richTextBox1.AppendText(sortOutput.ToString());
    }

    private static void SortOutputHandler(object sendingProcess,
        DataReceivedEventArgs outLine)
    {
            sortOutput.Append(Environment.NewLine +
                "[" + numOutputLines.ToString() + "] - " + outLine.Data);
        }
    }

因此，当sort.exe启动时，它会显示文本，我希望所有这些文本也实时显示在richtextbox中(我不想等待进程退出，然后读取所有输出)

我该怎么做？我的代码有任何错误的部分吗？谢谢

更新@botz

我在我的代码中添加了这个

 private void SortOutputHandler(object sendingProcess,
        DataReceivedEventArgs outLine)
    {

            sortOutput.Append(Environment.NewLine +
                "[" + numOutputLines.ToString() + "] - " + outLine.Data);
            richTextBox1.AppendText(sortOutput.ToString());


    }

但是它抛出了这个异常

Cross-thread operation not valid: Control 'richTextBox1' accessed from a thread other than the thread it was created on.

最佳答案

WaitForExit()会阻止您的UI线程，因此您看不到新的输出。
在单独的线程中等待该过程，或者将WaitForExit()替换为以下内容:

while (!sortProcess.HasExited) {
     Application.DoEvents(); // This keeps your form responsive by processing events
}

现在，在SortOutputHandler中，您可以直接将输出追加到文本框。但是您应该记住检查是否需要在UI线程上调用它。

您可以在处理程序中以这种方式检查它是否在UI线程上:

    if (richTextBox1.InvokeRequired) { richTextBox1.BeginInvoke(new DataReceivedEventHandler(SortOutputHandler), new[] { sendingProcess, outLine }); }
    else {
        sortOutput.Append(Environment.NewLine + "[" + numOutputLines.ToString() + "] - " + outLine.Data);
        richTextBox1.AppendText(sortOutput.ToString());
    }

关于c# - 如何将流程输出(控制台)重定向到richtextbox？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/6521475/