c++ - 我要在什么条件下进一步增加 5% 的折扣？

要支付的金额通常是通过将单价乘以销售数量来计算的。但是，以下情况适用:

如果售出的数量大于或等于价格中断数量，则 10% 的折扣是
给那个项目。

如果给予折扣，并且要支付的新金额超过 $1000.00，则再增加 5%
给予折扣。

如果没有打折，并且支付的金额超过 $1000.00，那么 5% 的折扣是
给定

#include <iostream>
using namespace std;
int main(){
    int items;
    int i=0;
    int item_num;
    double unit_price;
    double price_break;
    double quantity_sold;
    double amount_paid;
    double discount=0.00;
    double net_payment;

    amount_paid=unit_price*quantity_sold;
    if(quantity_sold>=price_break){
        discount=0.1*amount_paid;
        new_amount=amount_paid-discount
        //Quantity sold is more than price break which places discount at 10%
        net_payment=new_amount;
    }else{
        //Need help with this. How do I further add 5%?
        if((quantity_sold>=price_break)&&(new_amount>1000)){
            discount=0.1*amount_paid;
            net_payment=amount_paid-discount;
        }
        else{
            if(amount_paid>1000){
                // discount is 5% since the amount to be paid exceeds $1000
                discount=0.05*amount_paid;
                net_payment=amount_paid-discount;
            }
            else{
                if(quantity_sold<price_break){
                    //No discount and the amount to be paid doesn't exceeds $1000
                    net_payment=amount_paid;
                }
            }
        }
    }

最佳答案

由于第二个和第三个条件导致相同的事情发生，您可以将规则简化如下:

首先，如果售出的数量大于或等于价格中断数量，则对该商品给予 10% 的折扣。

无论在步骤 1 中是否给予折扣，如果要支付的金额超过 1,000 美元，则给予 5% 的折扣。

因此，只需去掉外部 else 中的 if 块，而只需测试金额是否超过 1,000 美元。

amount_paid=unit_price*quantity_sold;
if(quantity_sold>=price_break){
// apply first discount if quantity is high enough
    discount=0.1*amount_paid;
    amount_paid-=discount;
}
if(amount_paid>1000){
// discount is 5% since the amount to be paid exceeds $1000
    discount=0.05*amount_paid;
    amount_paid-=discount;
}

关于c++ - 我要在什么条件下进一步增加 5% 的折扣？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/53017686/