bash - 删除从文件捕获的元素

我在.mkv中有多个eng.md文件，按代码列出

    $ grep -i 'mkv' eng.md
    ./Volumes/Transcend/Downloads/The.Adventure.of.English.Ep4.mkv
    ./Volumes/Transcend/Downloads/The.Adventure.of.English.Ep5.mkv
    ./Volumes/Transcend/Downloads/The.Adventure.of.English.Ep6.mkv
    ./Volumes/Transcend/Downloads/The.Adventure.of.English.Ep7.mkv
    ./Volumes/Transcend/Downloads/._The.Adventure.of.English.Ep4.mkv
    ./Volumes/Transcend/Downloads/The.Adventure.of.English.Ep8.mkv
    ./Volumes/Transcend/Downloads/._The.Adventure.of.English.Ep8.mkv
    ./Volumes/Transcend/Downloads/._The.Adventure.of.English.Ep5.mkv
    ./Volumes/Transcend/Downloads/._The.Adventure.of.English.Ep6.mkv

我决定用管道方法删除mkv文件并尝试

$ rm < grep -i 'mkv' eng.md
-bash: grep: No such file or directory

交替尝试

$ grep -i 'mkv' eng.md | rm
usage: rm [-f | -i] [-dPRrvW] file ...
       unlink file
grep: eng.md: No such file or directory

如何解决这样的问题？

最佳答案

像这样，（除非是一大堆文件exceeds the command line maximum length）：

rm $(grep -i mkv eng.md)