node.js - 使用 typescript 创建 Mongoose 模型-子文档

我正在按照本文概述的Typescript实现 Mongoose 模型，并且不确定在处理子文档数组时这是如何转换的。假设我有以下模型和架构定义:

interface IPet {
    name: {type: mongoose.Types.String, required: true},
    type: {type: mongoose.Types.String, required: true}
}

export = IPet


interface IUser {
    email: string;
    password: string;
    displayName: string;
    pets: mongoose.Types.DocumentArray<IPetModel>
};

export = IUser;


import mongoose = require("mongoose");
import IUser = require("../../shared/Users/IUser");
interface IUserModel extends IUser, mongoose.Document { }

import mongoose = require("mongoose");
import IPet = require("../../shared/Pets/IPet");
interface IPetModel extends IPet, Subdocument { }

将新宠物添加到user.pet子文档的代码:

addNewPet = (userId: string, newPet: IPet){
    var _user = mongoose.model<IUserModel>("User", userSchema);
    let userModel: IUserModel = await this._user.findById(userId);
    let pet: IPetModel = userModel.pets.create(newPet);
    let savedUser: IUser = await pet.save();
}

在查看链接之后，这似乎是处理子文档所必需的理想方法。但是，这种情况似乎导致抛出CasterConstructor异常:

TypeError: Cannot read property 'casterConstructor' of undefined at Array.create.

使用上面链接的文章中概述的 Mongoose 模型时，处理子文档的正确方法是正确的吗？

最佳答案

你可以试试这个包https://www.npmjs.com/package/mongoose-ts-ua

@setSchema()
class User1 extends User {
    @prop()
    name?: string;

    @setMethod
    method1() {
        console.log('method1, user1');
    }
}

@setSchema()
class User2 extends User {
    @prop({ required: true })
    name?: string;

    @prop()
    child: User1;
}

export const User2Model = getModelForClass<User2, typeof User2>(User2);

用法

let u2 = new User2Model({ child: { name: 'u1' } });