公司数据库具有有关表ID，ORDER_DATE，STATUS，CUSTOMER_ID的信息，列名称表名称为ORDERS。
1. Need to extract the info which is not delivered.
2. If there is more than 5 orders select one with lowest order id.
3.Sort the output in the increasing order of order ID
表
ID,ORDER_DATE,STATUS,CUSTOMER_ID
10100,1-6-2003,PLACED,344
10101,2-6-2003,DELIVERED,544
10102,3-6-2003,IN TRANSIT,341
10103,4-6-2003,PLACED,343
10104,5-6-2003,IN TRANSIT,312
10105,6-6-2003,PLACED,390
10106,7-6-2003,PLACED,399
我的查询
select ID,ORDER_DATE,STATUS,CUSTOMER_ID from ORDERS where STATUS in ('IN TRANSIT', 'PLACED')order by ORDER_DATE desc limit 5;
我出来
52 2016-09-04 PLACED 87
10 2016-09-04 PLACED 252
40 2016-09-04 PLACED 989
62 2016-09-04 IN TRANSIT 780
45 2016-09-04 IN TRANSIT 527
预期中>
10100 2003-01-06 PLACED 363
10101 2003-01-06 PLACED 128
10102 2003-01-06 IN TRANSIT 181
10106 2003-01-07 IN TRANSIT 278
10120 2003-01-07 PLACED 114
最佳答案
我认为您只需要：
select ID, ORDER_DATE, STATUS, CUSTOMER_ID from ORDERS where STATUS <> 'DELIVERED' order by ID limit 5;
关于mysql - 如何联接一个表并限制同一表，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/58447209/