我正在尝试在服务器上上传图像,下面是我在Internet上找到的脚本,并且在本地工作时在部署代码和数据库时出现“无法打开流:权限被拒绝”错误。

<?php
//define a maxim size for the uploaded images in Kb
 define ("MAX_SIZE","5000");

//This function reads the extension of the file. It is used to determine if the file  is an image by checking the extension.
 function getExtension($str) {
         $i = strrpos($str,".");
         if (!$i) { return ""; }
         $l = strlen($str) - $i;
         $ext = substr($str,$i+1,$l);
         return $ext;
 }

//This variable is used as a flag. The value is initialized with 0 (meaning no error  found)
//and it will be changed to 1 if an errro occures.
//If the error occures the file will not be uploaded.
 $errors=0;

    //reads the name of the file the user submitted for uploading
    $image=$_FILES['image']['name'];

    //if it is not empty
    if ($image)
    {
    //get the original name of the file from the clients machine
        $filename = stripslashes($_FILES['image']['name']);
    //get the extension of the file in a lower case format
        $extension = getExtension($filename);
        $extension = strtolower($extension);
    //if it is not a known extension, we will suppose it is an error and will not  upload the file,
    //otherwise we will do more tests
 if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png"))
        {
        //print error message
            echo '<h1>Nepoznata vrsta fajla!</h1>';
            $errors=1;
        }
        else
        {
//get the size of the image in bytes
 //$_FILES['image']['tmp_name'] is the temporary filename of the file
 //in which the uploaded file was stored on the server
 $size=filesize($_FILES['image']['tmp_name']);

//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
    echo '<h1>To large file!</h1>';
    $errors=1;
}

//we will give an unique name, for example the time in unix time format
$image_name=time().'.'.$extension;
//the new name will be containing the full path where will be stored (images folder)
$newname="Content/Images/".$image_name;
//we verify if the image has been uploaded, and print error instead
//$copied = copy($_FILES['image']['tmp_name'], $newname);

$copied = copy('$_FILES['image']['tmp_name'], $newname);

//echo $_FILES['image']['tmp_name'].'<br/>';
//echo $_FILES['image']['name'];

if (!$copied)
{
    echo '<h1>Error occurred!</h1>';
    $errors=1;
}}}


//If no errors registred, print the success message
 /*if(isset($_POST['Submit']) && !$errors)
    {
    echo "<h1>You have successfully uploaded image.</h1>";
}*/

 ?>

我从stackoverflow看到了一些应答器,例如answers1answer2,但是我不确定该怎么做?还有其他建议吗?

谢谢。

最佳答案

确保运行php并执行此脚本的系统用户对您尝试直接存储文件的位置具有写权限。

关于php复制功能,无法打开流: Permission denied,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/5572251/

10-14 13:52