删除发送给Json MVC的对象的空属性

问题描述

namespace Booking.Areas.Golfy.Models
{
    public class Time
    {
        public string   time            { get; set; }
        public int      holes           { get; set; }
        public int      slots_available { get; set; }
        public decimal? price           { get; set; }
        public int?     Nextcourseid    { get; set; }

        public bool ShouldSerializeNextcourseid
        {
            get
            {
                return this.Nextcourseid != null;
            }
        }

        public bool? allow_extra { get; set; }

        public bool ShouldSerializeallow_extra
        {
            get
            {
                return this.allow_extra != null;
            }
        }
    }
}

namespace Booking.Areas.Golfy.Controllers
{
    public class TeetimesController : Controller
    {
        //
        // GET: /Golfy/Teetimes/
        public ActionResult Index(
            string date,
            int?   courseid = null,
            int?   clubid = null,
            int?   holes = null,
            int?   available = null,
            int?   prices = null
        )
        {
            var DateFrom = DateTime.ParseExact(date, "yyyy-MM-dd", CultureInfo.InvariantCulture);

            Teetimes r = BookingManager.GetBookings(new Code.Classes.Params.ParamGetBooking()
            {
                ClubID = clubid
                , DateFrom = DateFrom
                , DateTo = DateFrom.AddDays(1)
                , GroundID = courseid
            });

            return Json(r, JsonRequestBehavior.AllowGet);
        }
    }
}

上面的web服务返回一个带有几个时间的json字符串.

The webservice above returns a json string with several intance of Time.

我希望属性Nextcourseid和allow_extra在其值为空时不显示在输出中.

I'd like properties Nextcourseid and allow_extra to be left out of the output when their values are null.

我尝试过ShouldSerializeXxx，但它似乎不起作用.
FYI:我也尝试了[ScriptIgnore]，该方法可以工作，但不是有条件的.

I tried ShouldSerializeXxx but it doesn't seems to work.
FYI: I also tried [ScriptIgnore] which work but isn't conditional.

推荐答案

您不能使用默认的Json ActionResult删除空属性.

You can't use the default Json ActionResult to remove null properties.

您可以查看 JSON.NET ，它具有一个属性，您可以设置该属性以删除该属性(如果为空)

You can take a look at JSON.NET, it has an attribute that you can set to remove the property if it is null

[JsonProperty(NullValueHandling=NullValueHandling.Ignore)]

或者，如果您不想使用其他库，则可以创建自己的json自定义ActionResult并为默认的JavaScriptSerializer注册一个新的转换器，如下所示:

Or if you don't want to use other libraries you can create your own json custom ActionResult and register a new converter for the default JavaScriptSerializer, like this:

public class JsonWithoutNullPropertiesResult : ActionResult
{
    private object Data { get; set; }

    public JsonWithoutNullPropertiesResult(object data)
    {
        Data = data;
    }

    public override void ExecuteResult(ControllerContext context)
    {
        HttpResponseBase response = context.HttpContext.Response;
        response.ContentType = "application/x-javascript";
        response.ContentEncoding = Encoding.UTF8;

        if (Data != null)
        {
            JavaScriptSerializer serializer = new JavaScriptSerializer();
            serializer.RegisterConverters(new[] { new NullPropertiesConverter() });
            string ser = serializer.Serialize(Data);
            response.Write(ser);
        }
    }
}

public class NullPropertiesConverter : JavaScriptConverter
{
    public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
    {
        var toSerialize = new Dictionary<string, object>();

        foreach (var prop in obj.GetType()
                                .GetProperties(BindingFlags.Instance | BindingFlags.Public)
                                .Select(p => new
                                {
                                    Name = p.Name,
                                    Value = p.GetValue(obj)
                                })
                                .Where(p => p.Value != null))
        {
            toSerialize.Add(prop.Name, prop.Value);
        }

        return toSerialize;
    }

    public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
    {
        throw new NotImplementedException();
    }

    public override IEnumerable<Type> SupportedTypes
    {
        get { return GetType().Assembly.GetTypes(); }
    }
}

现在在您看来:

public ActionResult Index()
{
    Teetimes r = BookingManager.GetBookings();
    return new JsonWithoutNullPropertiesResult(t);
}

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