在Java中读取int形式的文件

问题描述

我有一个* .txt文件，其中包含这样的数据:

I have a *.txt file that it has data like this:

  1222 25 36 25 14 25 25 36 363 25 15
    1253 69 54 87 54 285
]±غ'Q­ہx¸'،2ذç12â· 'ئ‰؟¦خ&{3ع*U6هؤ­ر–¨ر،³ڑُ‌ں¢œغ)™پ÷ةtڑت†éYْ(زH5x¸2ش/¨#ژ‏ظœ,tx[Kh6"¨
rٹ±k'¨اqaيïذüـvqشQ­0H888/ ح‎lںR–>Kْ¹bف‘دô†)oŒىٹط.fNؤ8ک„ٌnpwَ§IMقJ™؟س5؛x.Zµ‎™7ˆے¨‌أئ°—لف):©¢چR¢سï¶J±@JœOْ‏5TMè§è9´«7 –دس54)ںشw>’âغ2›Zi@وûr&  طFو-dة ôƒ( œءxƒ§أh(¢ش‘»إV¨پ~ؤF؟!]&´ye\جہ„°?ّ!Uج3ص­wyc†P`¬:
ِS…ةّEژœ Zشâku‍ X§Rٌ¦ص«{â‹YwOڈ48¹Wٌ"i¾َه#™²|(³bˆiتژ-»çJ¯‍صl¦ر"+ءC’µہڈ™،£ظ(2€j¤ًگdك(`اء—꯳[f‌

其中的前17个字符为整数，其余的为二进制.

first 17 chars of that are integer and others are binary.

现在我想先阅读17个字符.我该怎么读?

now i want to read first 17 chars.how can i read them?

推荐答案

您可以使用 java.io.Scanner :

This is something you can do with a java.io.Scanner:

File f = new File("yourtxt.txt");
Scanner s = new Scanner(f);
for (int i = 0; i < 17 && s.hasNextInt(); ++i)
{
    int inputInteger = s.nextInt();
    // Handle your int here...
}

---

引发的异常可能是因为整数之间不需要字节.

---

The exception that is thrown is probably because of bytes you don't need between the integers.

也许您可以尝试执行以下操作:

Maybe you can try to do something like this:

DataInputStream dis = new DataInputStream(new FileInputStream(yourFile));
String numbers = dis.readLine() + " " + dis.readLine();
numbers = numbers.trim().replaceAll(" +", " ");
String[] array = numbers.split(" ");
for (int i = 0; i < array.length; ++i)
{
    int inputInteger = Integer.parseInt(array[i]);
    // handle inputInteger here...
}

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