本文介绍了un_active按钮,直到功能完成的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在UI中使用kivy.有一个耗时的函数,当它运行时,kivy ui会变成黑色,所以我使用了线程.我想禁用按钮,直到耗时"功能完成,然后再次启用按钮.我已经使用过类似如下的内容:

I am using kivy for UI. there is a Time_consuming function and when it runs, kivy ui will goes in black, so I used Threading.I want to disable buttons until Time_consuming function finishes, and then enable button again. I have been used something like below:

from threading import Thread
from kivy.clock import Clock
from functools import partial

   def run():
        self.run_button.disabled=True
        self.back_button.disabled=True

        t=Thread(target=Time_consuming(), args=())
        t.start()

        Clock.schedule_interval(partial(disable, t.isAlive()), 8)

    def disable(t, what):
        print(t)
        if not t:
            self.run_button.disabled=False
            self.back_button.disabled=False

但是这种方法不起作用,即使Time_easing()完成,disable()中的t.isAlive()也为True.问题出在哪里?

but this dose not work, t.isAlive() in disable() even when Time_consuming() finishes, is True. where is the problem ?

question2:另一个问题是Clock.schedule_interval将永远运行.函数完成后如何停止?

question2: another problem is, Clock.schedule_interval will continue to run for ever. how can stop it when function finished?

推荐答案

我发现:

question1:传递t而不是t.isAlive().this:

question1: pass t instead of t.isAlive().this :

Clock.schedule_interval(partial(disable, t.isAlive()), 8)

更改为:

Clock.schedule_interval(partial(disable, t), 8)

问题2:如果disable()返回False,则该计划将被取消,并且不会重复.

question2: If the disable() returns False, the schedule will be canceled and won’t repeat.

def run_model():
    self.run_button.disabled=True
    self.back_button.disabled=True

    t=Thread(target=run, args=())
    t.start()

    Clock.schedule_interval(partial(disable, t), 8)

def disable(t, what):
    if not t.isAlive():
        self.run_button.disabled=False
        self.back_button.disabled=False
        return False

这篇关于un_active按钮,直到功能完成的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-27 00:00