如何在不传递任何键的情况下从guava LoadingCache获取所有值

问题描述

我正在使用Guava LoadingCache来缓存一些结果。使用加载方法，我从其他来源获取结果，并使用 put（key，value）放入缓存。
现在我要解决的问题是：我想在不传递任何键的情况下获得该缓存中的所有可用结果。因为我有兴趣获取当时在缓存中显示的所有值，而不管任何特定键。

I am using Guava LoadingCache to cache some of the results. Using load method I fetch results from other source and put into cache using 'put(key,value)'.Now the problem I am trying to solve is: I want to get all the available results in that cache with out passing any keys. Because I am interested in taking all the values presented in the cache at that time regardless of any specific keys.

getall（Iterable< ;?键）或 getAllPresent（Iterable<？>键）方法，但是那些方法期望键可以通过。

getall(Iterable<?> keys) or getAllPresent(Iterable<?> keys) methods are there but those are expecting the keys to be passed.

推荐答案

您可以使用查看并操作返回的 ConcurrentMap 。番石榴：

You can use (Loading)Cache#asMap view and operate on returned ConcurrentMap. There's nice description on Guava wiki page:

• cache.asMap（）包含所有内容
  缓存中当前加载的条目。因此，例如， cache.asMap（）。keySet（）包含当前所有已加载的
  密钥。

• cache.asMap() contains all entries that are currently loaded in the cache. So, for example, cache.asMap().keySet() contains all the currently loaded keys.

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