问题描述
我需要使用嵌套for循环和 print('*',end ='')
来创建显示的模式:
这里是我的代码。
n = 0
print(模式A)
在范围内(0,11):
n = n + 1
(0,n-1):
print('*',end = '')
print()
print('')
print(Pattern B)
for b in range(0,11):
n = n - 1
for d(0,n + 1):
print('*',end ='')
print()
print('')
当我启动模式C和D时,我尝试以下操作:
$ p $ print(C模式)
在范围内(11,0,-1):
n = n + 1 $ b $ (0,n + 1):b $ b print('*',end ='')
print()
print('')
print(' (0,n-1):
在范围(11,0, print('*',end ='')
print()
和A和B是一样的编辑!
模式C和D都需要前导空格,并且不打印任何空格,只是星号。
下面是可以打印所需前导空格的替代代码:
print( C)
(11,0,-1):
print((11-e)*''+ e *'*')
print ('')
print(模式D)
在g范围内(11,0,-1):
print(g *''+(11-g)*' *')
以下是输出:
模式C
***********
**********
**** *****
********
*******
******
*****
****
***
**
*
模式D
*
**
***
****
*****
******
*******
*** *****
*********
**********
中更多细节,请考虑以下行:
print((11-e)*''+ e *'*')
打印(11-e)
空格, e
星星。如果您的老师需要嵌套循环,那么您可能需要将 print((11- e)*''+ e *'*')
循环打印每个空间,一次一个,然后是每个星星,一次一个。
模式C通过嵌套循环
如果你遵循了我给出的关于嵌套循环的提示,你将会得到如下模式C的解决方案:
$ p $
print(模式C)
在范围内(11,0,-1):
$ print((11-e)*''+ e *'*')
在范围(11-e)中的d:
print('',end ='')$ b (e):
print('*',end ='')
print()
I am required to use nested for loops and print('*', end=' ')
to create the pattern shown here:
And here is my code. I have figured out the first two.
n = 0
print ("Pattern A")
for x in range (0,11):
n = n + 1
for a in range (0, n-1):
print ('*', end = '')
print()
print ('')
print ("Pattern B")
for b in range (0,11):
n = n - 1
for d in range (0, n+1):
print ('*', end = '')
print()
print ('')
When i start pattern C and D, i try the following:
print ("Pattern C")
for e in range (11,0,-1):
n = n + 1
for f in range (0, n+1):
print ('*', end = '')
print()
print ('')
print ("Pattern D")
for g in range (11,0,-1):
n = n - 1
for h in range (0, n-1):
print ('*', end = '')
print()
But the result is the same as A and B. Help is appreciated!
Both patterns C and D require leading spaces and you are not printing any spaces, just stars.
Here is alternative code that prints the required leading spaces:
print ("Pattern C")
for e in range (11,0,-1):
print((11-e) * ' ' + e * '*')
print ('')
print ("Pattern D")
for g in range (11,0,-1):
print(g * ' ' + (11-g) * '*')
Here is the output:
Pattern C
***********
**********
*********
********
*******
******
*****
****
***
**
*
Pattern D
*
**
***
****
*****
******
*******
********
*********
**********
In more detail, consider this line:
print((11-e) * ' ' + e * '*')
It prints (11-e)
spaces followed by e
stars. This provides the leading spaces needed to make the patterns.
If your teacher wants nested loops, then you may need to convert print((11-e) * ' ' + e * '*')
into loops printing each space, one at a time, followed by each star, one at a time.
Pattern C via nested loops
If you followed the hints I gave about nested loops, you would have arrived at a solution for Pattern C like the following:
print ("Pattern C")
for e in range (11,0,-1):
#print((11-e) * ' ' + e * '*')
for d in range (11-e):
print (' ', end = '')
for d in range (e):
print ('*', end = '')
print()
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