有没有办法在通用(< T>)函数/类(Typescript)中获得通用类型的名称?

问题描述

这是我的功能的定义:

getData<T extends Entity> () { }

我目前不接受任何论点.我有办法在运行时将T转换为类型的字符串名称吗?也许使用typeof?

I don't currently accept any arguments. Is there a way for me to translate the T into the string name of the type at runtime? Perhaps using typeof?

我来自C#世界，您将在其中使用反射.但是，我是Java语言的新手，不知道这会是什么.

I am from the C# world where you would use reflection. However I am new to Javascript and not sure what the equivalent would be.

谢谢.

推荐答案

编译期间会删除类型，因此不会.您应该从不 从 具有一个通用函数，该函数在参数位置不使用其类型参数.

Types are erased during compilation, so no. You should never ever have a generic function that doesn't use its type parameter in an argument position.

假设getData适用于类，您可以编写类似以下内容的

Assuming getData works on classes, you could write something like:

class NotSureThisIsReallyAGoodIdea {
    static getData<T>(cls: new(...args: any[]) => T): T {
        /* magic happens */
        const url = 'http://example.com/' + cls['name'];
        return <T>undefined;
    }
}

class SomeShape {
    x: number;
}

let s = NotSureThisIsReallyAGoodIdea.getData(SomeShape);
s.x; // OK

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