__declspec分配的范围

问题描述

在C ++中，我有兴趣将指针变量声明为只读，我正在考虑通过以下机制：

  #pragma section（.readonly，read）
 __declspec（allocate（。readonly））
 VOID * g_pROData; //我想这是只读的
 
 VOID * g_pRWData; //我想这是读写
  

但是，我不知道__declspec语句。它将只包括g_pROdata，还是会包括g_pRWData呢？是否有任何方法改变范围？

谢谢。

解决方案

完整语法为：

  __declspec（allocate（segname））declarator 
  

所以它只适用于下面的声明，在你的情况下 g_pROData ，并在名为 .readonly 的段中分配。如果在该段中需要分配多个变量，则必须为每个变量重复声明。

In C++, I am interested in declaring a pointer variable as read-only, and I am considering to do that via the following mechanism:

#pragma section (".readonly", read)
__declspec(allocate(".readonly"))
VOID* g_pROData; // I want this to be read-only

VOID* g_pRWData; // I want this to be read-write

However, I am not sure about the scope of the __declspec statement. Would it include only g_pROdata, or would it include g_pRWData too? Is there any way to alter the scope?

Thanks.

解决方案

Full syntax is:

 __declspec(allocate("segname")) declarator

So it applies only to declaration that follows, in your case only g_pROData is affected and allocated in segment named .readonly. If more that one variable needs to be allocated in that segment then you have to repeat declaration for each one.

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