Javascript，重复对象键N次，其值为N

问题描述

我想知道如何以更清洁和最佳的方式执行此操作:

I was wondering how to do this in the more cleaner and optimal way:

我有一个具有以下结构的对象:

I have an Object with the following structure:

{
   "125": 2,
   "439": 3,
   "560": 1,
   "999": 2,
   ...
}

我想创建一个平面数组，该数组重复每个键，其值指示该键的次数.以及将键(字符串)转换为整数的加分点.在此示例中，结果数组应为:

I want to create a flat array repeating every key, the number of times indicated by its value. And bonus points for converting keys (strings) to integers. In this example, the resulting array should be:

[ 125, 125, 439, 439, 439, 560, 999, 999 ]

我尝试了几种方法，但是它们看起来都过度设计.当然，有一种更简单的方法.这就是我用下划线得到的(它返回一个字符串数组，也不是整数):

I've tried several ways but they all look over-engineered. For sure there is an easier way.This is what I've got with underscore (and it returns an Array of strings, nor integers):

_.compact(_.flatten(_.map(files, function(num, id) { 
     return new Array(num+1).join('$'+id).split('$') 
})))

我知道有很多方法可以做到这一点.我只想要一种干净快捷的方法.作为 Ruby 开发人员，它可能很容易:

I know there are plenty of ways to accomplish this. I just only want a clean and quick way. Being a Ruby developer it could be as easy as:

> files = {"125" => 2, "439" => 3, "560" => 1, "999" => 2}
 => {"125"=>2, "439"=>3, "560"=>1, "999"=>2} 
> files.map {|key, value| [key.to_i] * value}.flatten
 => [125, 125, 439, 439, 439, 560, 999, 999]

谢谢.

推荐答案

尝试一下:

var obj = {
  "125": 2,
  "439": 3,
  "560": 1,
  "999": 2
}

var arr = [];

for (prop in obj) {
  for (var i = 0; i < obj[prop]; i++)
    arr.push(parseInt(prop));
}

console.log(arr)

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