locals()['_ [1]']在Python中是什么意思?

问题描述

我看到了一个据称可以从从序列中删除重复项的衬里代码:

I saw a one liner code that is claimed to remove duplicates from a sequence:

u = [x for x in seq if x not in locals()['_[1]']]

我在ipython(使用python 2.7)中尝试了该代码，它给出了KeyError: '_[1]'

I tried that code in ipython (with Python 2.7), it gave KeyError: '_[1]'

['_[1]']在Python中是否有特殊含义?

Does ['_[1]'] mean something special in Python?

推荐答案

locals()['_[1]']是一种访问对列表理解(或生成器)当前结果的引用的方法.

locals()['_[1]'] is a way to access a reference to list comprehension (or generator) current result inside that list comprehension.

这是很邪恶的，但是会产生有趣的结果:

It is quite an evil, but can produce funny results:

>> [list(locals()['_[1]']) for x in range(3)]
[[], [[]], [[], [[]]]]

在此处查看更多详细信息: the-secret-列表名称.

See more details here: the-secret-name-of-list-comprehensions.

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