树上建可持久化trie即可,有点过于裸了。darkbzoj过了然而在bzoj一直wa,不知道哪有锅。

#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstdlib>
#include<cstring>
#include<algorithm>
using namespace std;
int read()
{
int x=,f=;char c=getchar();
while (c<''||c>'') {if (c=='-') f=-;c=getchar();}
while (c>=''&&c<='') x=(x<<)+(x<<)+(c^),c=getchar();
return x*f;
}
#define N 100010
int n,m,p[N],fa[N][],deep[N],root[N],t,cnt;
struct data{int to,nxt;char s[];
}edge[N<<];
struct data2{int x,ch[];
}tree[N*];
void addedge(int x,int y,char *s){t++;edge[t].to=y,edge[t].nxt=p[x],p[x]=t;memcpy(edge[t].s,s,sizeof(s));}
void ins(int &k,int p,char *s,int n)
{
tree[++cnt]=tree[k],k=cnt;tree[k].x++;
if (p==n) return;
ins(tree[k].ch[s[p+]-'a'],p+,s,n);
}
int query(int k,int p,char *s,int n)
{
if (!k) return ;
if (p==n) return tree[k].x;
return query(tree[k].ch[s[p+]-'a'],p+,s,n);
}
void dfs(int k)
{
for (int i=p[k];i;i=edge[i].nxt)
if (edge[i].to!=fa[k][])
{
fa[edge[i].to][]=k;
deep[edge[i].to]=deep[k]+;
root[edge[i].to]=root[k];
ins(root[edge[i].to],,edge[i].s,strlen(edge[i].s+));
dfs(edge[i].to);
}
}
int lca(int x,int y)
{
if (deep[x]<deep[y]) swap(x,y);
for (int j=;~j;j--) if (deep[fa[x][j]]>=deep[y]) x=fa[x][j];
if (x==y) return x;
for (int j=;~j;j--) if (fa[x][j]!=fa[y][j]) x=fa[x][j],y=fa[y][j];
return fa[x][];
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("bzoj4477.in","r",stdin);
freopen("bzoj4477.out","w",stdout);
const char LL[]="%I64d\n";
#else
const char LL[]="%lld\n";
#endif
n=read();
for (int i=;i<n;i++)
{
int x=read(),y=read();
char s[];scanf("%s",s+);
addedge(x,y,s);
}
dfs();
fa[][]=;
for (int j=;j<;j++)
for (int i=;i<=n;i++)
fa[i][j]=fa[fa[i][j-]][j-];
m=read();
while (m--)
{
int x=read(),y=read();
char s[];scanf("%s",s+);
printf("%d\n",query(root[x],,s,strlen(s+))+query(root[y],,s,strlen(s+))-(query(root[lca(x,y)],,s,strlen(s+))<<));
}
return ;
}
04-30 09:30